How do you find the derivative of #s(t)=t^3-2t+4#?

Question

1621 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-11-29T09:51:10

#s'(t)=3t^2-2#. See explanation.

The Power Rule states that for any real constant #alpha# the derivative of #f(x)=x^alpha# is:

#(x^alpha)'=alpha*x^(alpha-1)#

By using this rule we can calculate that:

#(t^3-2t+4)'=3t^2-2#