How do you find the derivative of $ln (x^{\frac{1}{2}})$ $ln(x^(1/2))$ ?

Question

How do you find the derivative of $ln (x^{\frac{1}{2}})$ $ln(x^(1/2))$ ?

1 Answer

Impact of this question

24172 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-10-21T15:47:45

$\frac{d}{d x} {ln x}^{\frac{1}{2}} = \frac{1}{2 x}$ $d/dxlnx^(1/2) = 1/(2x)$

Explanation:

Use the properties of logs: ${log a}^{b} = b log a$ $log a^b=bloga$ and the natural log derivative, $\frac{d}{d x} ln x = \frac{1}{x}$ $d/dxlnx=1/x$

so $\frac{d}{d x} {ln x}^{\frac{1}{2}} = \frac{d}{d x} (\frac{1}{2} ln x)$ $d/dxlnx^(1/2) = d/dx(1/2lnx)$
$:. d/dxlnx^(1/2) = 1/2 d/dx(lnx)$
$:. d/dxlnx^(1/2) = 1/2 1/x$
$:. d/dxlnx^(1/2) = 1/(2x)$

Science

Math

Humanities

... and beyond

How do you find the derivative of $ln (x^{\frac{1}{2}})$ $ln(x^(1/2))$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you find the derivative of ln(x^(1/2))ln(x12) ln(x^(1/2))?

1 Answer

Explanation:

Related questions

Impact of this question

How do you find the derivative of $ln (x^{\frac{1}{2}})$ $ln(x^(1/2))$ ?