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How do you find the derivative of # ln(x^(1/2))#?

1 Answer

Oct 21, 2016

# d/dxlnx^(1/2) = 1/(2x) #

Explanation:

Use the properties of logs: #log a^b=bloga# and the natural log derivative, # d/dxlnx=1/x #

so #d/dxlnx^(1/2) = d/dx(1/2lnx) #
# :. d/dxlnx^(1/2) = 1/2 d/dx(lnx) #
# :. d/dxlnx^(1/2) = 1/2 1/x #
# :. d/dxlnx^(1/2) = 1/(2x) #

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