How do you find the derivative of # ln(x^(1/2))#? Calculus Differentiating Exponential Functions Differentiating Exponential Functions with Calculators 1 Answer Steve M Oct 21, 2016 # d/dxlnx^(1/2) = 1/(2x) # Explanation: Use the properties of logs: #log a^b=bloga# and the natural log derivative, # d/dxlnx=1/x # so #d/dxlnx^(1/2) = d/dx(1/2lnx) # # :. d/dxlnx^(1/2) = 1/2 d/dx(lnx) # # :. d/dxlnx^(1/2) = 1/2 1/x # # :. d/dxlnx^(1/2) = 1/(2x) # Answer link Related questions How do you use a calculator to find the derivative of #f(x)=e^(x^2)# ? How do you use a calculator to find the derivative of #f(x)=e^(1-3x)# ? How do you use a calculator to find the derivative of #f(x)=e^sqrt(x)# ? What is the derivative of #e^(-x)#? What is the derivative of #ln(2x)#? How do you differentiate #(lnx)^(x)#? How do you differentiate #x^lnx#? How do you differentiate #f(x) = e^xlnx#? How do you differentiate #e^(lnx) #? How do you differentiate #y = lnx^2#? See all questions in Differentiating Exponential Functions with Calculators Impact of this question 22846 views around the world You can reuse this answer Creative Commons License