How do you differentiate #f(x) = e^xlnx#?

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Answer 1 · 2016-05-24T06:35:38

#d f(x)=(e^x/x+e^x*l n (e)*l n(x))*d x#

#f(x)=e^x*l n x ?#

#d/(d x) (e^x)=e^x*l n(e)#

#d/(d x) l n(x)=1/x#

#y=a.b#

#y^'=a^'*b+b^'*a#

#d f(x)=(e^x*l n(e)*l n (x)+1/x*e^x)* d x#

#"or:"#

#d f(x)=(e^x/x+e^x*l n (e)*l n(x))*d x#