How do you find the derivative of $ln -x$ ?

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Answer 1 · 2016-06-28T15:20:44

$d/dx ln (-x) = 1/x$

as a rule $d/dx ln (f(x)) = 1/f(x) f'(x)$

here $f(x) = - x$ and $f'(x) = -1$ so we have

$d/dx ln (-x) = 1/(-x)*-1 = 1/x$

How do you find the derivative of ln -x ln -x?