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How do you find the derivative of #h(s)=s^(4/5)-s^(2/3)#?

1 Answer

Feb 17, 2017

#h'(s) = 4/(5 root(5)s) - 2/(3 root(3) s)#

Explanation:

#h(s)=s^(4/5)-s^(2/3)#

#h'(s) = 4/5 s^((4/5-1)) - 2/3 s^((2/3-1))#

#h'(s) = 4/5 s^((-1/5)) - 2/3 s^((-1/3))#

#h'(s) = 4/(5 s^((1/5))) - 2/(3 s^((1/3))#

#h'(s) = 4/(5 root(5)s) - 2/(3 root(3) s)#

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