How do you find the derivative of #g(t)=t^-2#? Calculus Basic Differentiation Rules Power Rule 1 Answer Dylan K. Dec 12, 2016 #g'(t)=-2t^-3# Explanation: Use the product rule which says #d/dx[x^n]=nx^(n-1)# Answer link Related questions How do you find the derivative of a polynomial? How do you find the derivative of #y =1/sqrt(x)#? How do you find the derivative of #y =4/sqrt(x)#? How do you find the derivative of #y =sqrt(2x)#? How do you find the derivative of #y =sqrt(3x)#? How do you find the derivative of #y =sqrt(x)#? How do you find the derivative of #y =sqrt(x)# using the definition of derivative? How do you find the derivative of #y =sqrt(3x+1)#? How do you find the derivative of #y =sqrt(9-x)#? How do you find the derivative of #y =sqrt(x-1)#? See all questions in Power Rule Impact of this question 1407 views around the world You can reuse this answer Creative Commons License