How do you find the derivative of #f(x) = (x^2-4)/(x-2) #? Calculus Basic Differentiation Rules Quotient Rule 1 Answer Jim H Oct 4, 2016 #f'(x)=1# for #x != 2#. Explanation: #x^2-4 = (x+2)(x-2)#, so we can reduce quotient for #x != 2#. #f(x) = x+2# for #x != 2#, so #f'(x) = 1# for #x != 2#. Answer link Related questions What is the Quotient Rule for derivatives? How do I use the quotient rule to find the derivative? How do you prove the quotient rule? How do you use the quotient rule to differentiate #y=(2x^4-3x)/(4x-1)#? How do you use the quotient rule to differentiate #y=cos(x)/ln(x)#? How do you use the quotient rule to find the derivative of #y=tan(x)# ? How do you use the quotient rule to find the derivative of #y=x/(x^2+1)# ? How do you use the quotient rule to find the derivative of #y=(e^x+1)/(e^x-1)# ? How do you use the quotient rule to find the derivative of #y=(x-sqrt(x))/(x^(1/3))# ? How do you use the quotient rule to find the derivative of #y=x/(3+e^x)# ? See all questions in Quotient Rule Impact of this question 1124 views around the world You can reuse this answer Creative Commons License