How do you find the derivative of #f(x)=ln(2x^2+1)#? Calculus Differentiating Logarithmic Functions Differentiating Logarithmic Functions without Base e 1 Answer Krzysztof S. Nov 7, 2016 #(4x)/(2x^2+1)# Explanation: "Function Composition" #(f(g(x)))'= f’(g(x))g’(x)# #g(x)' = (2x^2+1)'= 4x# #f'(ln() ) = 1/g(x)= 1/(2x^2+1)# #(f(g(x)))'= f’(g(x))g’(x) = 1/(2x^2+1) * 4x= (4x)/(2x^2+1)# Answer link Related questions What is the derivative of #f(x)=log_b(g(x))# ? What is the derivative of #f(x)=log(x^2+x)# ? What is the derivative of #f(x)=log_4(e^x+3)# ? What is the derivative of #f(x)=x*log_5(x)# ? What is the derivative of #f(x)=e^(4x)*log(1-x)# ? What is the derivative of #f(x)=log(x)/x# ? What is the derivative of #f(x)=log_2(cos(x))# ? What is the derivative of #f(x)=log_11(tan(x))# ? What is the derivative of #f(x)=sqrt(1+log_3(x)# ? What is the derivative of #f(x)=(log_6(x))^2# ? See all questions in Differentiating Logarithmic Functions without Base e Impact of this question 3944 views around the world You can reuse this answer Creative Commons License