How do you find the derivative of #f(x)=6sqrtx+5cosx#? Calculus Basic Differentiation Rules Power Rule 1 Answer bp Feb 16, 2017 #3/sqrtx -5sin x# Explanation: #f'(x) = d/dx (6sqrtx) + d/dx (5 cos x)# =#6(1/2 1/sqrt x) -5 sin x# =#3/sqrtx -5sin x# Answer link Related questions How do you find the derivative of a polynomial? How do you find the derivative of #y =1/sqrt(x)#? How do you find the derivative of #y =4/sqrt(x)#? How do you find the derivative of #y =sqrt(2x)#? How do you find the derivative of #y =sqrt(3x)#? How do you find the derivative of #y =sqrt(x)#? How do you find the derivative of #y =sqrt(x)# using the definition of derivative? How do you find the derivative of #y =sqrt(3x+1)#? How do you find the derivative of #y =sqrt(9-x)#? How do you find the derivative of #y =sqrt(x-1)#? See all questions in Power Rule Impact of this question 1729 views around the world You can reuse this answer Creative Commons License