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How do you find the derivative of #f(x)=2/3x^3-x^2-24x-4#?

1 Answer

Jul 24, 2016

By the power rule:

#f'(x) =3 xx 2/3x^(3 - 1) - 1 xx 2x^(2 - 1) - 1 xx 24x^(1 - 1) - 0 xx 4x^(0 - 1)#

#f'(x) = 2x^2 - 2x - 2#

Hopefully this helps!

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