How do you find the derivative of # f(x)=(1/x^2)#? Calculus Basic Differentiation Rules Quotient Rule 1 Answer Ratnaker Mehta Jun 20, 2016 #f'(x)=-2x^-3.# Explanation: #y=x^n rArr dy/dx=nx^(n-1).# Given that #f(x)=1/x^2=x^-2.# Hence, #f'(x)=-2x^(-2-1), = -2x^-3.# Answer link Related questions What is the Quotient Rule for derivatives? How do I use the quotient rule to find the derivative? How do you prove the quotient rule? How do you use the quotient rule to differentiate #y=(2x^4-3x)/(4x-1)#? How do you use the quotient rule to differentiate #y=cos(x)/ln(x)#? How do you use the quotient rule to find the derivative of #y=tan(x)# ? How do you use the quotient rule to find the derivative of #y=x/(x^2+1)# ? How do you use the quotient rule to find the derivative of #y=(e^x+1)/(e^x-1)# ? How do you use the quotient rule to find the derivative of #y=(x-sqrt(x))/(x^(1/3))# ? How do you use the quotient rule to find the derivative of #y=x/(3+e^x)# ? See all questions in Quotient Rule Impact of this question 1166 views around the world You can reuse this answer Creative Commons License