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How do you find the derivative of #f(x)=1/(3-2x)#?

1 Answer

Jul 27, 2018

#f'(x)=2/(3-2x)^2#

Explanation:

Here ,

#f(x)=1/(3-2x)=(3-2x)^-1#

Diff.w.r.t. #x# , #"using "color(blue)"chain rule :"#

#f'(x)#=#(-1)/(3-2x)^2d/(dx)(3-2x)to[becaused/(du)(u)^-1=-1(u)^-2]#

#:.f'(x)=(-1)/(3-2x)^2(-2)#

#:.f'(x)=2/(3-2x)^2#

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