How do you find the derivative of #f(t) = cos((pit)/4)#?

Question

5476 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-04-11T21:05:20

Here you can use the Chain Rule to derive #cos# first and then its argument to get:
#f'(t)=-sin(pit/4)*pi/4=-pi/4sin(pit/4)#