How do you find the derivative of $e^{x {(3 x^{2} + 2 x - 1)}^{2}}$ $e^(x(3x^2 + 2x-1)^2$ ?

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Answer 1 · 2015-03-28T18:15:13

The answer is:

$y'=e^(x(3x^2 + 2x-1)^2)[1*(3x^2 + 2x-1)^2+x*2(3x^2 + 2x-1)*(6x+2)]=$

$=e^(x(3x^2 + 2x-1)^2)(3x^2 + 2x-1)(3x^2 + 2x-1+12x^2+4x)=$

$=e^(x(3x^2 + 2x-1)^2)(3x^2 + 2x-1)(15x^2+6x-1)$ .

How do you find the derivative of e^(x(3x^2 + 2x-1)^2ex(3x2+2x−1)2e^(x(3x^2 + 2x-1)^2?