How do you find the derivative of #e^(x(3x^2 + 2x-1)^2#? Calculus Differentiating Exponential Functions Differentiating Exponential Functions with Base e 1 Answer Massimiliano Mar 28, 2015 The answer is: #y'=e^(x(3x^2 + 2x-1)^2)[1*(3x^2 + 2x-1)^2+x*2(3x^2 + 2x-1)*(6x+2)]=# #=e^(x(3x^2 + 2x-1)^2)(3x^2 + 2x-1)(3x^2 + 2x-1+12x^2+4x)=# #=e^(x(3x^2 + 2x-1)^2)(3x^2 + 2x-1)(15x^2+6x-1)#. Answer link Related questions What is the derivative of #y=3x^2e^(5x)# ? What is the derivative of #y=e^(3-2x)# ? What is the derivative of #f(theta)=e^(sin2theta)# ? What is the derivative of #f(x)=(e^(1/x))/x^2# ? What is the derivative of #f(x)=e^(pix)*cos(6x)# ? What is the derivative of #f(x)=x^4*e^sqrt(x)# ? What is the derivative of #f(x)=e^(-6x)+e# ? How do you find the derivative of #y=e^x#? How do you find the derivative of #y=e^(1/x)#? How do you find the derivative of #y=e^(2x)#? See all questions in Differentiating Exponential Functions with Base e Impact of this question 2703 views around the world You can reuse this answer Creative Commons License