Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

How do you find the derivative of #cos[sqrt (x)]#?

1 Answer

Jim H · AJ Speller

Oct 28, 2015

Use the chain rule.

Explanation:

#d/dx(sqrtx) =d/dx(x^(1/2)) =1/2x^(1/2-1)=1/2x^(1/2-2/2)=1/2x^(-1/2)=1/(2x^(1/2))= 1/(2sqrtx)#

#d/dx(cos(sqrtx)) = -sin(sqrtx) d/dx(sqrtx)#

# = -sin(sqrtx) (1/(2sqrtx))#

Related questions

See all questions in Derivative Rules for y=cos(x) and y=tan(x)

Impact of this question

40867 views around the world

You can reuse this answer
Creative Commons License