How do you find the derivative of #cos^5(w)*6cos(w^5)#? Calculus Differentiating Trigonometric Functions Derivative Rules for y=cos(x) and y=tan(x) 1 Answer Sonnhard Jun 2, 2018 #-30sin(w)*cos^4(w)*cos(w^5)-30*sin(w^5)*cos^5(w)*w^4# Explanation: Using the product rule and the chain rule we get #5cos^4(w)*(-sin(w))*6*cos(w^5)+cos^5(w)*6*(-sin(w^5))*5w^4# Answer link Related questions What is the derivative of #y=cos(x)# ? What is the derivative of #y=tan(x)# ? How do you find the 108th derivative of #y=cos(x)# ? How do you find the derivative of #y=cos(x)# from first principle? How do you find the derivative of #y=cos(x^2)# ? How do you find the derivative of #y=e^x cos(x)# ? How do you find the derivative of #y=x^cos(x)#? How do you find the second derivative of #y=cos(x^2)# ? How do you find the 50th derivative of #y=cos(x)# ? How do you find the derivative of #y=cos(x^2)# ? See all questions in Derivative Rules for y=cos(x) and y=tan(x) Impact of this question 1778 views around the world You can reuse this answer Creative Commons License