How do you find the derivative of #cos^2(x^3)#? Calculus Differentiating Trigonometric Functions Derivative Rules for y=cos(x) and y=tan(x) 1 Answer Michael Aug 28, 2015 #f'(x)=-6x^(2).cos(x^(3)).sin(x^(3))# Explanation: #f(x)=cos^2(x^3)# Apply the chain rule: #f'(x)=-2cos(x^3).sin(x^3).3x^2# #f'(x)=-6x^(2).cos(x^3).sin(x^3)# Answer link Related questions What is the derivative of #y=cos(x)# ? What is the derivative of #y=tan(x)# ? How do you find the 108th derivative of #y=cos(x)# ? How do you find the derivative of #y=cos(x)# from first principle? How do you find the derivative of #y=cos(x^2)# ? How do you find the derivative of #y=e^x cos(x)# ? How do you find the derivative of #y=x^cos(x)#? How do you find the second derivative of #y=cos(x^2)# ? How do you find the 50th derivative of #y=cos(x)# ? How do you find the derivative of #y=cos(x^2)# ? See all questions in Derivative Rules for y=cos(x) and y=tan(x) Impact of this question 1310 views around the world You can reuse this answer Creative Commons License