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How do you find the derivative of #(4x +x^-5)^⅓#?

1 Answer

Feb 21, 2016

#d/dx(4x+x^-5)^(1/3)=1/3(4x+x^-5)^(-2/3)*(4-5x^-6)#

Explanation:

Use the power rule : #d/dx[u(x)]^n=n[u(x)]^(n-1)*(du)/dx#

#therefore d/dx(4x+x^-5)^(1/3)=1/3(4x+x^-5)^(-2/3)*(4-5x^-6)#

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