How do you find the derivative of #3/2 t^(1/2)#? Calculus Basic Differentiation Rules Power Rule 1 Answer Sasha P. Oct 18, 2015 #(3sqrtt)/(4t)# Explanation: #y'=3/2*1/2*t^(1/2-1) = 3/4 t^(-1/2) = 3/(4t^(1/2)) = 3/(4sqrtt)*sqrtt/sqrtt=(3sqrtt)/(4t)# Answer link Related questions How do you find the derivative of a polynomial? How do you find the derivative of #y =1/sqrt(x)#? How do you find the derivative of #y =4/sqrt(x)#? How do you find the derivative of #y =sqrt(2x)#? How do you find the derivative of #y =sqrt(3x)#? How do you find the derivative of #y =sqrt(x)#? How do you find the derivative of #y =sqrt(x)# using the definition of derivative? How do you find the derivative of #y =sqrt(3x+1)#? How do you find the derivative of #y =sqrt(9-x)#? How do you find the derivative of #y =sqrt(x-1)#? See all questions in Power Rule Impact of this question 1515 views around the world You can reuse this answer Creative Commons License