How do you find the derivative of #(2x+8)/(x-8)#?

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How do you find the derivative of #(2x+8)/(x-8)#?

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Answer 1 · 2016-10-21T18:14:49

# d/dx((2x+8)/(x-8)) = (-24)/(x-8)^2 #

Explanation:

You need to use the quotient rule; # d/dx(u/v) = (v(du)/dx-u(dv)/dx)/v^2 #

# d/dx((2x+8)/(x-8)) = ((x-8)d/dx(2x+8) - (2x+8)d/dx(x-8))/(x-8)^2 #
# :. d/dx((2x+8)/(x-8)) = ((x-8)(2) - (2x+8)(1))/(x-8)^2 #
# :. d/dx((2x+8)/(x-8)) = (2x-16-2x-8)/(x-8)^2 #
# :. d/dx((2x+8)/(x-8)) = (-24)/(x-8)^2 #

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How do you find the derivative of #(2x+8)/(x-8)#?

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