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How do you find the derivative of #(2x)/(3+e^x)#?

1 Answer

Mar 7, 2018

#(6+2e^x - 2xe^x)/(3+e^x)^2 #

Explanation:

We can use quotient rule:

#d/dx(f/g) = (gf' - fg')/g^2 #

If #f(x) = 2x# and #g(x) = 3 + e^x#, the derivative is

#(2(3+e^x) - 2x(e^x))/(3+e^x)^2 = (6+2e^x - 2xe^x)/(3+e^x)^2 #

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