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How do you find the derivative of #2x^2+x-1#?

1 Answer

Apr 13, 2017

#dy/dx(2x^2+x-1)=4x+1#

Explanation:

Use the power rule #r(a)^(r-1)# and recall that the derivative of a constant is #0#

Therefore the derivative is,

#dy/dx=2*2x^(2-1)+1x^(1-0)-0#

#dy/dx=4x+1#

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