How do you find the derivative of #(2x^2 -5)^3(x^3 +6x)^(4/3)#? Calculus Basic Differentiation Rules Power Rule 1 Answer Sonnhard May 24, 2018 #4(x^3+6x)^(1/3)(2x^2-5)^2(5x^4+15x^2-10)# Explanation: By the product and the chain rule we get #3(2x^2-5)^2*4x(x^3+6x)^(4/3)+(2x^2-5)^3*4/3(x^3+6x)^(1/3)(3x^2+6)# which simplifies to my answer Answer link Related questions How do you find the derivative of a polynomial? How do you find the derivative of #y =1/sqrt(x)#? How do you find the derivative of #y =4/sqrt(x)#? How do you find the derivative of #y =sqrt(2x)#? How do you find the derivative of #y =sqrt(3x)#? How do you find the derivative of #y =sqrt(x)#? How do you find the derivative of #y =sqrt(x)# using the definition of derivative? How do you find the derivative of #y =sqrt(3x+1)#? How do you find the derivative of #y =sqrt(9-x)#? How do you find the derivative of #y =sqrt(x-1)#? See all questions in Power Rule Impact of this question 1448 views around the world You can reuse this answer Creative Commons License