Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

How do you find the derivative of #2e^-x#?

1 Answer

Oct 31, 2016

#(dy)/(dx)=-2e^-x#

Explanation:

Recall that #d/dxe^x=e^x#

Using chain rule, #(dy)/(dx)=(dy)/(du)*(du)/(dx)#,

Let #u=-x#

#(dy)/(du)=d/(du)2e^u=2e^u=2e^-x#

#(du)/(dx)=d/(dx)-x=-1#

#:.(dy)/(dx)=-1*2e^-x=-2e^-x#

Related questions

See all questions in Differentiating Exponential Functions with Base e

Impact of this question

9538 views around the world

You can reuse this answer
Creative Commons License