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How do you find the derivative of #1/(x^3-x^2)#?

1 Answer

Jan 29, 2017

#(2-3x)/(x^3(x-1)^2)#

Explanation:

#f'(x)=-(3x^2-2x)/(x^3-x^2)^2#

#=-(cancelx(3x-2))/(x^(cancel4^3)(x-1)^2)#

#=(2-3x)/(x^3(x-1)^2)#

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