How do you find the derivative of #1/x^3#?
1 Answer
Jan 16, 2017
#dy/dx=(-3)/(x^(2))#
Explanation:
Given -
#y=1/x^3#
Rewrite it as -
#y=x^(-3)#
#dy/dx=(-3)(x^(-3+1))#
#dy/dx=-3x^(-2)#
Rewrite it as -
#dy/dx=(-3)/(x^(2))#
