How do you find the derivative for #y=(3x)/(x+5)#?

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Answer 1 · 2018-06-11T05:40:03

#(dy)/(dx)=15/(x+5)^2#

#y=(3x)/(x+5)#

#y=3timesx/(x+5)#

#(dy)/(dx)=3 times ((x+5)(1)-(x)(1))/(x+5)^2#

#(dy)/(dx)=3 times (x+5-x)/(x+5)^2#

#(dy)/(dx)=3 times 5/(x+5)^2#

#(dy)/(dx)=15/(x+5)^2#

The quotient rule is given by:
#y=u/v#

#(dy)/(dx)=(vu'-uv')/v^2#