How do you find the derivative for #f(x)=sinxcosx#?

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How do you find the derivative for #f(x)=sinxcosx#?

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Answer 1 · 2015-03-28T01:45:25

You can use the Product Rule:
if: #k(x)=f(x)g(x)#
#k'(x)=f'(x)g(x)+f(x)g'(x)#
In your case:
#f'(x)=cos(x)cos(x)+sin(x)(-sin(x))=#
#=cos^2(x)-sin^2(x)=cos(2x)#

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How do you find the derivative for #f(x)=sinxcosx#?

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