How do you find the derivative for #d/dx (2x+1)/(x^2-1)#? Calculus Basic Differentiation Rules Quotient Rule 1 Answer Nallasivam V Sep 5, 2015 #dy/dx =( [(x^2 - 1) (2)] - [(2x + 1) (2x)])/(x^2 - 1) # #dy/dx =( [2x^2 - 2] - [4x^2 + 2x]) /(x^2 - 1)# #dy/dx =( 2x^2 - 2 - 4x^2 - 2x) /(x^2 - 1)# #dy/dx =( - 2x^2 - 2x - 2) /(x^2 - 1)# Answer link Related questions What is the Quotient Rule for derivatives? How do I use the quotient rule to find the derivative? How do you prove the quotient rule? How do you use the quotient rule to differentiate #y=(2x^4-3x)/(4x-1)#? How do you use the quotient rule to differentiate #y=cos(x)/ln(x)#? How do you use the quotient rule to find the derivative of #y=tan(x)# ? How do you use the quotient rule to find the derivative of #y=x/(x^2+1)# ? How do you use the quotient rule to find the derivative of #y=(e^x+1)/(e^x-1)# ? How do you use the quotient rule to find the derivative of #y=(x-sqrt(x))/(x^(1/3))# ? How do you use the quotient rule to find the derivative of #y=x/(3+e^x)# ? See all questions in Quotient Rule Impact of this question 4061 views around the world You can reuse this answer Creative Commons License