How do you find the axis of symmetry and vertex point of the function: #y = 2x^2 + 24x + 62#?

1 Answer
bhaskar m.
Jun 9, 2018

The Axis of Symmetry occurs at #x=-6#
The Vertex occurs at #(x,y)=(-6, -10)#

Explanation:

The axis of symmetry of a quadratic equation is always located at #x=\frac{-b}{2a}# which in this case is equal to #\frac{-24}{2\cdot2}=-6#.

#\therefore# Axis of Symmetry occurs at #x=-6#

The vertex is the point that the function takes at the axis of symmetry.

#\therefore# in the case of this problem, the vertex is #(-6,f(-6))# which is equal to #(-6, -10)#

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