How do you find the average value of the function for #f(x)=1-x^4, -1<=x<=1#?
1 Answer
Aug 30, 2017
The average value is
Explanation:
The average value is given by
#A = 1/(b - a) int_a^b f(x)dx#
Where
#A = 1/(1 - (-1)) int 1 - x^4#
#A = 1/2[(x - 1/5x^5)]_-1^1#
#A = 1/2(1 - 1/5 - (-1 - 1/5(-1)^5))#
#A = 1/2(4/5 + 1 - 1/5)#
#A = 1/2(8/5)#
#A = 4/5#
Hopefully this helps!
