How do you find the average value of #f(x)=x^5-2x^3+x# as x varies between #[-1,0]#?
1 Answer
Feb 15, 2018
Explanation:
#"the average value is found using"#
#•color(white)(x)1/(b-a)int_a^bf(x)#
#"where "[a,b]=[-1,0]#
#rArr1/(0-(-1))int_(-1)^0(x^5-2x^3+x)dx#
#=[1/6x^6-1/2x^4+1/2x^2]_(-1)^0#
#=0-(1/6-1/2+1/2)=-1/6#
