How do you find the area of a rectangular object which has a length of 5 square root of 8 inches and a width of 2 square root of 5 inches?

1 Answer
Oct 4, 2016

#20sqrt10" square inches"#

Explanation:

The area ( A) of a rectangle is #color(red)(bar(ul(|color(white)(a/a)color(black)(A=lxxb)color(white)(a/a)|)))#
where l is the length and b, the width.

here #l=5sqrt8" and " b=2sqrt5#

#rArrA=5sqrt8xx2sqrt5#

#color(orange)"Reminder " color(red)(bar(ul(|color(white)(a/a)color(black)(sqrtaxxsqrtbhArrsqrt(ab))color(white)(a/a)|)))#

#rArrA=color(blue)(5)xxcolor(red)(sqrt8)xxcolor(blue)(2)xxcolor(red)(sqrt5)#

#=color(blue)(10)xxcolor(red)(sqrt40)#

Now #sqrt40=sqrt(4xx10)=sqrt4xxsqrt10=2xxsqrt10#

#rArrA=color(blue)(10)xxcolor(red)(sqrt40)=10xx2xxsqrt10#

#rArrA=20xxsqrt10=20sqrt10" square inches"#