How do you find the antiderivative of #e^-x#?

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How do you find the antiderivative of #e^-x#?

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Answer 1 · 2016-11-16T05:55:44

#= - e^(-x) + C#

Explanation:

Let
#" "#
#u(x) = e^(-x) #
#" "#
# du(x) = - e^(-x)dx#
#" "#
#rArr - du(x) = e^(-x)dx#
#" "#
#" "#
#inte^(-x)dx#
#" "#
#= int-du(x)#
#" "#
#=-u(x) + C" " C# is a constant
#" "#
#= - e^(-x) + C#

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How do you find the antiderivative of #e^-x#?

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