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How do you find the antiderivative of #e^(2x) dx#?

1 Answer

Shwetank Mauria

Jun 30, 2016

#inte^(2x)dx=1/2e^(2x)+c#

Explanation:

Let #u=2x#, hence #du=2dx#

Hence #inte^(2x)dx=inte^u*(du)/2#

= #1/2e^(u)+c#

= #1/2e^(2x)+c#

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