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How do you find the antiderivative of #(cosx)^2#?

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1 Answer

Shwetank Mauria

Jul 27, 2016

#intcos^2xdx=x/2+(sin2x)/4+c#

Explanation:

To find antiderivative i.e. integral of #cos^2x#, we can use formula #cos^2x=1/2(1+cos2x)#

#intcos^2xdx=int[1/2(1+cos2x)]dx#

= #int(1/2+(cos2x)/2)dx#

= #1/2[x+(sin2x)/2]+c#

= #x/2+(sin2x)/4+c#

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