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How do you find the antiderivative of #cos^3 (x)dx#?

1 Answer

Jun 23, 2016

# sin x- 1/3 sin^3x + C#

Explanation:

#\int cos^3 x \ dx = = \int cosx(cos^2x) \ dx= \int cosx(1-sin^2x) \ dx# and that's pretty much it

because

# \int cosx(1-sin^2x) \ dx#

# = \int cosx- cosx sin^2x \ dx#

# = sin x- 1/3 sin^3x + C#

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