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How do you find the antiderivative #4 + 4tan^2x#?

1 Answer

Apr 14, 2015

4tan x +C

4+4 #tan^2#x would be 4 (1 + #tan^2#x) or 4 #sec^2#x

Antiderivative of #sec^2# x is tanx. Hence the required answer would be 4tanx+C

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