How do you find the amplitude, phase shift and period of #Y = – 23 Cos (3X – π / 6) + 8#?

1 Answer
Jim G.
Mar 11, 2016

amplitude = 23 , #"period"= (2pi)/3" and phase shift "= (-pi/6)#

Explanation:

The standard form of the function is :

y = acos (bx + c ) + d

where |a| = amplitude , period = #(2pi)/b#

c = phase shift and d , a translation #((0),(d))#

here amplitude = |-23|= 23 , period# = (2pi)/3 #

phase shift =# (-pi/6) " move to the right " #

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