How do you find the amplitude, period, phase shift for #y=sin2x#?

1 Answer
Jim G.
Jan 31, 2017

#1,pi," no phase shift"#

Explanation:

The standard form of the #color(blue)"sine function"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=asin(bx+c)+d)color(white)(2/2)|)))#

#"where amplitude "=|a|," period " =(2pi)/b#

#"phase shift "=-c/b" and vertical shift "=d#

#"here "a=1,b=2,c=0,d=0#

#rArr"amplitude "=|1|=1," period "=(2pi)/2=pi#

Since c = 0 there is no phase shift.

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