How do you find the amplitude, period, phase shift for #y=sin1.5x#?

Question

1899 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-01T08:59:44

Amplitude #a = 1#

Period # = (2pi) / |1.5| = 4.1888#

Phase shift # = c / b = 0 / 1.5 = 0 # (shift to the right)

Use the form #y = a sin (bx - c) + d#

To find amplitude, period and phase shift.

Given #y = sin (1.5x)#

graph{sin(1.5x) [-10, 10, -5, 5]}

Amplitude #a = 1#

Period # = (2pi) / |1.5| = 4.1888#

Phase shift # = c / b = 0 / 1.5 = 0 # (shift to the right)