How do you find the amplitude, period, phase shift for #y=sin(x-pi/4)#?

1 Answer
Jim G.
Nov 27, 2016

#1,2pi,pi/4#

Explanation:

The standard form of the #color(blue)"sine function"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=asin(bx+c)+d)color(white)(2/2)|)))#

where amplitude = | a | , period #=(2pi)/b#

phase shift #=-c/b# and vertical shift = d

Here a = 1 , b = 1 , c #=-pi/4# and d = 0

#rArr"amplitude "=|1|=1," period "=(2pi)/1=2pi#

#"and phase shift "=-(-pi/4)/1=pi/4#

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