How do you find the amplitude, period, asymptotes (from 0-2pi), shifts, and the min/max of the following trig functions #Y= 2tan ( theta - pi/4)#?

1 Answer
Somebody N.
Nov 9, 2017

See below.

Explanation:

The tan function has no max/min value and consequently no amplitude. This is because:

as #theta-> pi/2, tan(theta)-> oo# and is undefined

The shift is #pi/4#, this can be seen from #2tan(theta-pi/4)# subtracting #pi/4# shifts the axis to the left, or the graph to the right. This can therefore be viewed either way.

Vertical asymptotes will occur where the function is undefined. This can be calculated using:

#theta-pi/4=pi/2# and #theta-pi/4=(3pi)/2# ( this is for the given interval )

#theta-pi/4=pi/2=>theta=color(blue)((3pi)/4)#

#theta-pi/4=(3pi)/2=>theta=color(blue)((7pi)/4)#

Period.

This can be found from two values where the tangent is zero. i.e.

#theta-pi/4=0=>theta=pi/4 and theta=(5pi)/4#

#(5pi)/4-pi/4=pi#

So:

Amplitude Doesn’t exist due to being undefined.

Period #color(white)(*)pi#

max/min Doesn’t exist due to being undefined.

shift #color(white)(*)pi/4#

Asymptotes At #(3pi)/4 and (7pi)/4#

Graph:

enter image source here

Related questions
See all questions in Amplitude, Period and Frequency
Impact of this question
3571 views around the world
You can reuse this answer
Creative Commons License