How do you find the amplitude, period, and shift for #y=sin (3x-pi/4)#?

1 Answer
Narad T.
Oct 20, 2016

#Amplitude =1#
#Period=(2pi)/3#
phase (shift) # = pi/4 # to the right

Explanation:

Let #y=asin(bx+c)#
The amplitude is the coefficient #a# of the sine, here it is 1
The period depends on the coefficient b of x, So here we have #3#
So the peroid #=(2pi)/3#, if the coefficient was 1, the period is #2pi#
The phase shift depends on the value and sign of c: Here it is #-pi/4# So it is #pi/4# to the right

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