How do you find the amplitude, period and phase shift of #y= -3 sin (2x + pi/2)#?

1 Answer
Jim G.
May 13, 2016

#3 , pi and pi/2#

Explanation:

The standard form of the sine wave function is

#color(red)(|bar(ul(color(white)(a/a)color(black)(y=asin(bx+c)+d)color(white)(a/a)|)))#

where |a| is the amplitude , period#=(2pi)/b#

c , represents the phase-shift and d , the vertical shift.

here amplitude = |-3| = 3 , period#=(2pi)/2=pi#

phase-shift#=pi/2#and vertical shift = 0

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