How do you find the amplitude, period, and phase shift of #3y=sin 2(x+1)#?

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Answer 1 · 2018-06-01T02:50:59

As below.

Standard form of the sine function is

#y = A sin(Bx - C) + D#

Given # 3y = sin (2x + 1)#

Writing it in standard form,

#y = (1/3) sin (2x + 2)#

#Amplitude = |A| = (1/3)#

Period #= (2pi)/|B| = (2pi)/2 = pi#

Phase Shift # = -C / B = -2/2 = -1#, 1 to the left.

Vertical Shift # = D = 0#