How do you find the amplitude, period and phase shift for #y=3cos(theta-pi/3)#?

1 Answer
Jim G.
Jan 17, 2017

#3,2pi,pi/3#

Explanation:

The standard form of the #color(blue)"cosine function"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=acos(bx+c)+d)color(white)(2/2)|)))#

#"where amplitude " =|a|," period " =(2pi)/b#

#"phase shift " =-c/b" and vertical shift " =d#

#"here " a=3,b=1,c=-pi/3" and " d=0#

#rArr"amplitude " =|3|=3," period " =(2pi)/1=2pi#

#"and phase shift " =-(-pi/3)/1=pi/3#

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