How do you find the amplitude, period and phase shift for #y=1/3sintheta+7#?

1 Answer
Jim G.
Jan 4, 2018

#1/3,2pi,0#

Explanation:

#"the standard form of the sine function is"#

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=asin(bx+c)+d)color(white)(2/2)|)))#

#"where the amplitude "=|a|," period "=(2pi)/b#

#"phase shift "=-c/b" and vertical shift "=d#

#"here "a=1/3,b=1,c=0" and "d=7#

#rArr"amplitude "=|1/3|=1/3." period=2pi#

#"there is no phase shift and vertical shift "=7#

Related questions
See all questions in Amplitude, Period and Frequency
Impact of this question
1040 views around the world
You can reuse this answer
Creative Commons License