How do you find the amplitude, period and phase shift for #y=1/2tantheta+1#?

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Answer 1 · 2018-06-20T04:07:58

As below.

#y = A tan (Bx - C) + D# is the standard form.

#y = (1/2) tan theta + 1#

#Amplitude = |A| = |(1/2)| = 1/2#

#"Period " = pi / |B| = pi / 1 = pi#

#"Phase Shift " = -C / B = 0#

#"Vertical Shift " = D = 1#

graph{(1/2) tan x + 1 [-10, 10, -5, 5]}