How do you find the amplitude and period of #y=sin(-5x)#?

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Answer 1 · 2015-07-09T20:41:43

#a = 2, T = 2/5 pi#

#f(x) = A sin (Bx + C)# or #g(x) = A cos (Bx + C)#

Repair that #-1 <= sin u <= 1#

Then #-A <= A sin u <= A#

Amplitude #a = A - (-A) = 2A#

For period, repair that #sin(u + 2k pi) = sin u = sin(-u)#

#Bx_0 + C = 0 \Rightarrow x_0 = -C/B#

#Bx_1 + C = 2 pi \Rightarrow x_1 = (2 pi-C)/B#

Period #T = x_1 - x_0 = (2 pi-C)/B + C/B = (2 pi) / B#

In your case, #A = 1, B = 5, C= 0#